JAMB - Chemistry (2000 - No. 5)
How many moles of HCl will be required to react with potassium heptaoxodichromate (VI) to produce 3 moles of chlorine?
14
12
11
10
Explanation
K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + HCl → Cl\(_{2}\) + KCl + CrCl\(_{3}\) + H\(_{2}\)O
Balancing the equation, we have
K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + 14HCl → 3Cl\(_{2}\) + 2KCl + 2CrCl\(_{3}\) + 7H\(_{2}\)O
Comments (0)
