First write a dissociation equation: H\(_2\)SO\(_4\)  ⇌  2H\(^+\)  +  SO\(_4\)\(^{2-}\)

Number of moles = \(\frac{Number of ions}{Avogadro number}\)

But we need to get the number of moles first by applying  n = \(\frac{m}{M}\)

  n = \(\frac{4.9}{98}\) (Molar mass of H\(_2\)SO\(_4\) = 98g/mol)

  n = 0.05 mole

Number of moles = \(\frac{Number of ions}{Avogadro number}\)

Number of hydrogen ions = ( n x L ) X 2 → We multiplied by 2 because 2H\(^+\) were formed.

 = 0.05 x 2 x 6.02 x 10\(^{23}\)

 = 6.02 x 10\(^{22}\) ions