Given:

T\(_1\) = 273K V\(_1\) = X P\(_1\) = Y → Let x and y represent the initial volume and initial pressure respectively.

T\(_2\) = ? V\(_2\) = 2X P\(_2\) = 2Y → Since the volume and pressure were doubled.

Using the formula, \(\frac{P_1 V_1}{T_1}\) =  \(\frac{P_2 V_2}{T_2}\)

  T\(_2\) =  \(\frac{P_2 V_2 T_1}{P_1 V_1}\)

 = \(\frac{2Y\times 2X \times 273}{Y\times X}\)

 = 2 X 2 X 273

 T\(_2\)= 1092K