JAMB - Chemistry (1986 - No. 44)
The relationship between the velocity (U) of gas molecules and their relative molecular mass (M) is shown by the equation
U = (kM)\(\frac{1}{2}\)
U = (kM)2
U = \(\sqrt{\frac{k}{m}}\)
U = \(\frac{k}{m}\)
Explanation
The relationship between (U) of a gas molecule and the relative molecular mass is \(\bar{U}\) = (\(\frac{k}{m}\))\(^{\frac{1}{2}}\)
or \(\bar{U}\) = \(\sqrt{\frac{k}{m}}\)
or \(\bar{U}\) = \(\sqrt{\frac{k}{m}}\)
Comments (0)
