JAMB - Chemistry (1982 - No. 32)
An element X has two isotopes, \(^{20} _{10}X\) and \(^{22} _{10}X\),
present in the ratio 1:3. The relative atomic mass of X would be?
present in the ratio 1:3. The relative atomic mass of X would be?
20.5
21.0
21.5
22.0
22.5
Explanation
The relative atomic mass will be [(20 * 1) + (3 * 22)] / (4)
(86)/(4) = (43)/(2) = 21.5
(86)/(4) = (43)/(2) = 21.5
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