JEE MAIN - Physics (2010 - No. 2)
If a source of power $$4kW$$ produces $${10^{20}}$$ photons/second, the radiation belongs to a part of the spectrum called
$$X$$ -rays
ultraviolet rays
microwaves
$$\gamma $$ - rays
Explicação
Power, $$P = {{nhv} \over t}$$
$$ \Rightarrow v = {{P \times t} \over {nh}}$$
$$ = {{4 \times {{10}^3} \times 1} \over {{{10}^{20}} \times 6.63 \times {{10}^{ - 34}}}} = 6 \times {10^{16}}Hz$$
$$ \Rightarrow v = {{P \times t} \over {nh}}$$
$$ = {{4 \times {{10}^3} \times 1} \over {{{10}^{20}} \times 6.63 \times {{10}^{ - 34}}}} = 6 \times {10^{16}}Hz$$