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JEE MAIN - Physics (2003 - No. 14)

A particle of mass $$M$$ and charge $$Q$$ moving with velocity $$\overrightarrow v $$ describe a circular path of radius $$R$$ when subjected to a uniform transverse magnetic field of induction $$B.$$ The network done by the field when the particle completes one full circle is
$$\left( {{{M{v^2}} \over R}} \right)2\pi R$$
zero
$$B\,\,Q\,2\pi R$$
$$B\,Qv\,2\pi R$$

Explicação

The work done, $$dW = Fds\,\cos \,\theta $$

The angle between force and displacement is $${90^ \circ }.$$

Therefore work done is zero.

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