JEE MAIN - Chemistry (2004 - No. 5)
For the reaction, CO(g) + Cl2(g) $$\leftrightharpoons$$ COCl2(g) the $${{{K_p}} \over {{K_c}}}$$ is equal to :
$$\sqrt {RT} $$
RT
1/RT
1.0
Explicação
$${K_p} = {K_c}{\left( {RT} \right)^{\Delta n}};$$
Here $$\Delta n = 1 - 2 = - 1$$
$$\therefore$$ $${{{k_p}} \over {{K_c}}} = {1 \over {RT}}$$
Here $$\Delta n = 1 - 2 = - 1$$
$$\therefore$$ $${{{k_p}} \over {{K_c}}} = {1 \over {RT}}$$