ExamPlay Light Logo
Entrar

JAMB - Physics (2004 - No. 27)

A 100kg box is pushed along a road with force of 500N. If the box moves with a uniform velocity, the coefficient of friction between the box and the road is
0.4
1.0
0.8
0.5

Explicação

Coefficient of friction μ = F/R = F/mg = 500/1000 = 0.5
∴ μ = 0.5

Comentários (0)

Faça login para comentar
Anúncio
BrainBehindX Inc Logo
©2026; Distribuído por BrainBehindX Inc