ExamPlay Dark Logo
Entrar

JAMB - Physics (1994 - No. 28)

An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral displacement of the object if the refractive index of the glass is 1.5.
1.0cm
1.5cm
2.0cm
2.5cm

Explicação

1.5 = \(\frac{3}{\text {apparent displacement}}\)

Apparent depth = 2cm

displacement = 3 - 2

= 1cm

Comentários (0)

Faça login para comentar
Anúncio
BrainBehindX Inc Logo
©2026; Distribuído por BrainBehindX Inc