ExamPlay Light Logo
Entrar

JAMB - Mathematics (2006 - No. 33)

If the locus of the points which are equidistant from point P and Q meets line PQ at point N, then PN equals
NQ
1/4NQ
2NQ
1/2NQ

Explicação

Locus of point equidistant from points P and Q is a perpendicular bisector of the straight joining P and Q
∴PN = NQ

Comentários (0)

Faça login para comentar
Anúncio
BrainBehindX Inc Logo
©2026; Distribuído por BrainBehindX Inc