JAMB - Chemistry (2024 - No. 38)
When Sulphur(IV)oxide is passed into solution of acidified tetraoxomanganate(VII), the colour changes from
blue to green
pink to yellow
purple to colourless
Orange to green
Explicação
When sulphur dioxide (SO\(_2\) gas is passed through an acidified potassium permanganate (KMnO\(_4\)) solution, the solution changes from purple to colourless. This is because of a redox reaction, where KMnO\(_4\) acts as an oxidizing agent and SO\(_2\) acts as a reducing agent.