WAEC - Physics (2017 - No. 11)
A motorist travelling at 72\(kmh^{-1}\) had his eyes shut for 0.4s during a hard sneeze. Calculate the distance covered by him during this time interval.
50.0m
28.8m
18.0m
8.0m
Wyjaśnienie
Convert velocity from \(kmh^{-1}\) to \(ms^{-1}\), by multiplying \(\frac{1000}{3600}\),
\(72 \times \frac{1000}{3600}\) = \(20ms^{-1}\)
Therefore, distance covered in 0.4s = \(20 \times 0.4 = 8m\)