WAEC - Physics (2002 - No. 35)
Three capacitors each of capacitance 18\(\mu F\) are connected in series. Calculate the effective capacitance of the capacitors
54.00\(\mu F\)
18.00\(\mu F\)
6.00\(\mu F\)
0.17\(\mu F\)
Wyjaśnienie
\(\frac{1}{c} = \frac{1}{18} + \frac{1}{18} + \frac{1}{18} = \frac{3}{18}\)
c = 6\(\mu F\)
c = 6\(\mu F\)