WAEC - Mathematics (2018 - No. 29)
Expression 0.612 in the form \(\frac{x}{y}\), where x and y are integers and y \(\neq\) 0
\(\frac{153}{250}\)
\(\frac{68}{111}\)
\(\frac{61}{100}\)
\(\frac{21}{33}\)
Wyjaśnienie
0.612 = \(\frac{0.612}{1}\) x \(\frac{1000}{1000}\)
= \(\frac{612}{1000}\)
= \(\frac{153}{250}\)