WAEC - Mathematics (2014 - No. 27)
A man's eye level is 1.7m above the horizontal ground and 13m from a vertical pole. If the pole is 8.3m high, calculate, correct to the nearest degree, the angle of elevation of the top of the pole from his eyes.
33o
32o
27o
26o
Wyjaśnienie
tan \(\theta = \frac{opp}{adj} = \frac{6.6}{13}\)
tan \(\theta = 0.5077\)
\(\theta\) = tan-1 0.5077
\(\theta = 27^o\)
tan \(\theta = 0.5077\)
\(\theta\) = tan-1 0.5077
\(\theta = 27^o\)