WAEC - Mathematics (1991 - No. 39)
If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is
o
2/15
4/14
11/15
1
Wyjaśnienie
P(X \(\cup\) Y) = \(\frac{1}{3} + \frac{2}{5}\)
= \(\frac{11}{15}\)
P(X \(\cup\) Y) = \(\frac{1}{3} + \frac{2}{5}\)
= \(\frac{11}{15}\)