WAEC - Chemistry (2018 - No. 35)
The empirical formula of a compound containing 0.067mol Cu and 0.066mol O is [Cu = 63.5, O = 16]
\(Cu_{2}O\)
\(CuO\)
\(CuO_{2}\)
\(CuO_{4}\)
Wyjaśnienie
Cu : O
0.067 : 0.066
mole ratio \(\frac{0.067}{0.066}\) : \(\frac{0.066}{0.066}\)
= 1 : 1
= CuO