WAEC - Chemistry (2016 - No. 17)
How many moles of oxygen would contain 1.204 x 1024 molecules?
[Avogadro's constant (NA) = 6.02 x 1023]
[Avogadro's constant (NA) = 6.02 x 1023]
1
2
3
4
Wyjaśnienie
6.02 x 1023 molecules is 1mole
1.204 x 1024 molecules will be......
\(\frac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\frac{1.204 \times 10}{6.02}\) = \(\frac{12.04}{6.02}\) = 2moles
1.204 x 1024 molecules will be......
\(\frac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\frac{1.204 \times 10}{6.02}\) = \(\frac{12.04}{6.02}\) = 2moles