JEE Advance - Mathematics (2004 - No. 22) | ExamPlay

Zalogować się

JEE Advance - Mathematics (2004 - No. 22)

For all $$'x',{x^2} + 2ax + 10 - 3a > 0,$$ then the interval in which '$$a$$' lies is

$$a < - 5$$

$$ - 5 < a < 2$$

$$a > 5$$

$$2 < a < 5$$

Uwagi (0)

Reklama