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JEE Advance - Chemistry (1982 - No. 16)

At room temparature, ammonia gas at 1 atm pressure and hydrogen chloride gas at P atm pressure are allowed to effuse through identical pin holes from opposite ends of a glass tube of one metre length and of uniform cross-section. Ammonium chloride is first formed at a distance of 60 cm from the end through which HCL gas is sent in. What is the value of P?
2.41 atm
3.62 atm
4.83 atm
6.04 atm
7.25 atm

Wyjaśnienie

If t is the time taken for the formation of ammonium chloride by the combination of NH3 and HCl, then

$${r_{HCl}} = {{60} \over t}$$ ; $${r_{N{H_3}}} = {{40} \over t}$$

The rate of diffusion, r is proportional to the root mean square velocity (u) which is equal to $$\sqrt {{{3P} \over d}} $$.

$$r \propto u \propto {{{3P} \over d}} $$

$$\therefore$$ $${{{r_{HCl}}} \over {{r_{N{H_3}}}}} = {{60/t} \over {40/t}} = {{\sqrt {{{3{P_{HCl}}} \over {{d_{HCl}}}}} } \over {\sqrt {{{3{P_{N{H_3}}}} \over {{d_{N{H_3}}}}}} }}$$

or $${{60} \over {40}} = {{\sqrt {{{3{P_{HCl}}} \over {18.25}}} } \over {\sqrt {{{3 \times 1\,atm} \over {8.5}}} }}$$

or $${\left( {{{60} \over {40}}} \right)^2} = {{3{P_{HCl}}} \over {18.25}} \times {{8.5} \over {3\,atm}}$$

or $${P_{HCl}} = {{60 \times 60} \over {40 \times 40}} \times {{18.25} \over {8.5}}$$ atm = 4.83 atm

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