JEE MAIN - Physics (2004 - No. 10)
The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index $$n$$) is :
$${\tan ^{ - 1}}\left( {1/n} \right)$$
$${\sin ^{ - 1}}\left( {1/n} \right)$$
$${\sin ^{ - 1}}\left( n \right)$$
$${\tan ^{ - 1}}\left( n \right)$$
Wyjaśnienie
The angle of incidence for total polarization is given by
$$\tan \theta = n \Rightarrow \theta = {\tan ^{ - 1}}n$$
Where $$n$$ is the refractive index of the glass.
$$\tan \theta = n \Rightarrow \theta = {\tan ^{ - 1}}n$$
Where $$n$$ is the refractive index of the glass.