JEE MAIN - Chemistry (2004 - No. 1)
An ideal gas expands in volume from 1$$\times$$10-3 m3 to 1 $$\times$$ 10-2 m3 at 300 K against a constant pressure of 1$$\times$$105 Nm-2. The work done is :
-900 J
900 kJ
270 kJ
-900 kJ
Wyjaśnienie
$$w = - P\Delta V = - {10^{ - 5}}\left( {1 \times {{10}^{ - 2}} - 1 \times {{10}^{ - 3}}} \right)$$
$$ = - 900J$$
$$ = - 900J$$