JAMB - Physics (2024 - No. 27)
How much joules of heat are given out when a piece of iron, of mass 60g and specific heat capacity 460JKg\(^{-1}\)K\(^{-1}\), cools from 75ºC to 35ºC
1000J
1050J
1067J
1104J
Wyjaśnienie
Quantity of heat Q = mass of iron x specific heat capacity of iron x change in temperature.
Q = mc\(\delta\)\(\theta\)
m = 60g ⇒ 0.060, c = 460Jkg\(^{-1}\)k\(^{-1}\) and \(\delta\)\(\theta\) = 75 - 35 = 40ºC
Q = 0.060 x 460 x 40 = 1104J.