JAMB - Physics (2013 - No. 10)
Calculate the work done when a force of 20N stretches a spring by 50mm.
0.5J
1.5J
2.0J
2.5J
Wyjaśnienie
W = \(\frac{1}{2}Fe\)
W = \(\frac{1}{2}\times 20 \times 0.05\)
W = 0.5J
W = \(\frac{1}{2}\times 20 \times 0.05\)
W = 0.5J