JAMB - Physics (1980 - No. 7)
A given quantity of heat increases the temperature of 150grams of water from 9oC to 15oC and increases the temperature of oil of 100grams from 9oC to 25oC. The ratio of the specific heat of oil to that of water is
0.36
0.46
0.56
0.76
0.86
Wyjaśnienie
Heat lost = heat gained
moCo\(\theta\)o = mwCw\(\theta\)w
100 x Co x (25 - 9) = 150 x Cw x (15 - 9)
\(\frac{C_w}{C_w}\) = 0.56
moCo\(\theta\)o = mwCw\(\theta\)w
100 x Co x (25 - 9) = 150 x Cw x (15 - 9)
\(\frac{C_w}{C_w}\) = 0.56