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JAMB - Mathematics (2007 - No. 41)

Find the locus of point equidistant from two straight lines y - 5 = 0 and y - 3 = 0
y - 2 = 0
y - 4 = 0
y - 1 = 0
y - 3 = 0

Wyjaśnienie

Locus of point P equidistant from y - 5 = 0 and y - 3 = 0 is y = 4 i.e y - 4 = 0

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