JAMB - Mathematics (2000 - No. 42)
If the diagram is the graph of y = x\(^2\), the shaded area is
64 square units
\(\frac{128}{3}\) square units
32 square units
\(\frac{64}{3}\) square units
Wyjaśnienie
A = \(\int^{x = 4}_{x = 0}\) ydx = \(\int^{4}_{0}\)16 - x\(^2\)dx = [16 - \(\frac{x^3}{3} + c]^{4}_{0}\)
= \(\frac{128}{3}\) square units
= \(\frac{128}{3}\) square units