JAMB - Mathematics (1992 - No. 42)
The probability of an event P is \(\frac{3}{4}\) while that of another event Q is \(\frac{1}{6}\). If the probability of both P and Q is \(\frac{1}{2}\). What is the probability of either P or Q.
\(\frac{1}{96}\)
\(\frac{1}{8}\)
\(\frac{5}{6}\)
\(\frac{11}{12}\)
Wyjaśnienie
Prob of P = \(\frac{3}{4}\)
Prob of Q = \(\frac{1}{6}\)
Prob of both P or Q = \(\frac{3}{4} + \frac{1}{6} = \frac{11}{12}\)