JAMB - Physics (1983 - No. 24)
a force of 16N applied 4.0kg block that is at rest on a smooth, horizontal surface. What is the velocity of the block at t = 5 seconds?
4ms-1
10ms-1
20ms-1
50ms-1
80ms-1
Forklaring
F = ma
= \(\frac{m(u - v)}{t}\)
16 = \(\frac{4(v - 0)}{5}\)
v = 20ms-1
= \(\frac{m(u - v)}{t}\)
16 = \(\frac{4(v - 0)}{5}\)
v = 20ms-1