ExamPlay Light Logo
Inloggen

WAEC - Physics (1994 - No. 18)

A battery of e.m.f 10V an internal resistance 2Ω is connected to a resistance of 6Ω. Calculate the p.d
8.75V
7.50V
5V
2.50V
1.25V

Uitleg

V = E - Ir = 10V - \(\frac{10 \times 2}{8}\) = 7.5V

Opmerkingen (0)

Advertentie