WAEC - Mathematics (2019 - No. 9)
If 6, P, and 14 are consecutive terms in an Arithmetic Progression (AP), find the value of P.
9
10
6
8
Uitleg
6, p, 14
14 - p = p - 6
14 + 6 = p - 6
14 + 6 = p + p
\(\frac{2p}{2}\)
= \(\frac{20}{2}\)
p = 10
6, p, 14
14 - p = p - 6
14 + 6 = p - 6
14 + 6 = p + p
\(\frac{2p}{2}\)
= \(\frac{20}{2}\)
p = 10