JEE Advance - Mathematics (1999 - No. 18)

If the roots of the equation $${x^2} - 2ax + {a^2} + a - 3 = 0$$ are real and less than 3, then

$$a < 2$$

$$2 \le a \le 3$$

$$3 < a \le 4$$

$$a > 4$$

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