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JAMB - Physics (2017 - No. 28)

From the diagram above, calculate the energy stored in the capacitor
4.0 x 10\(^{-2}\)J
4.0 x 10\(^{-4}\)J
8.0 x 10\(^{-4}\)J
8.0 x 10\(^{-2}\)J

Uitleg

c = 8µF, v = 10v

Energy stored = \(\frac{1}{2}\) cv2

= \(\frac{1}{2}\) × (8 × 10− 6) × 102

= 4 × 10\(^{-4}\)

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