JAMB - Physics (1989 - No. 27)
Three resistors, with substances 250\(\Omega\), 500\(\Omega\) and 1k\(\Omega\) are connected in series. A 6V battery is connected to either end of the combination. Calculate the pot3ential difference between the end of the 250\(\Omega\) resistor.
0.20V
0.86V
1.71V
3.43V
Penjelasan
Using voltage - divider method
v1 = \(\frac{(R_1)}{R_T}\)VT
= \(\frac{250}{1750}\) x \(\frac{6}{1}\)
= 0.86V
v1 = \(\frac{(R_1)}{R_T}\)VT
= \(\frac{250}{1750}\) x \(\frac{6}{1}\)
= 0.86V