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JAMB - Mathematics (1995 - No. 30)

For what value of x is the tangent to the curve y = x\(^2\) - 4x + 3 parallel to the x-axis?
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Penjelasan

At the point where the tangent is parallel to the x- axis, the slope of the curve = 0.

Given: \(y = x^{2} - 4x + 3\)

\(\frac{\mathrm d y}{\mathrm d x} = 2x - 4\)

\(2x - 4 = 0 \implies 2x = 4 \)

\(x = 2\)

When x = 2, the tangent of the curve is parallel to the x- axis.

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