JAMB - Chemistry (1999 - No. 26)
RS(aq) + HF(aq) → RF(s) + HS(aq)
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
the heat content of the reactants is lower than that of the products
the heat content of the reactants is higher than that of the products
the reaction is slow
a large amount of heat is absorbed