WAEC - Physics (2016 - No. 24)
The distance between two successive trough of a wave is 0.4m. If the frequency of the source is 825Hz, Calculate the speed of the wave
165.0 ms-1
330.0ms-1
41.5ms-1
85.0ms-1
Тайлбар
v = f\(\lambda\)
= 825 x 0.4
= 330.0ms-1
= 825 x 0.4
= 330.0ms-1