WAEC - Physics (2003 - No. 8)
A ball f mass 5.0kg hits a smooth vertical wall normally with a speed of 2ms-1. Determine the magnitude of the resulting impulse
2.0kgms-1
10.0kgms-1
5.0kgms-1
2.5kgms-1
Тайлбар
I = Ft = m(v - u) = 5 x 2
= 10kgms-1
= 10kgms-1