WAEC - Mathematics (2024 - No. 8)
If log\(_3^{2x - 1}\) = 5, find the value of x
8
16
64
122
Тайлбар
log\(_3^{2x - 1}\) = 5 in index form becomes 3\(^5\) = 2x - 1
2x - 1 = 243
2x = 243 + 1 = 244
x = \(\frac{244}{2}\) = 122
log\(_3^{2x - 1}\) = 5 in index form becomes 3\(^5\) = 2x - 1
2x - 1 = 243
2x = 243 + 1 = 244
x = \(\frac{244}{2}\) = 122