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WAEC - Mathematics (2021 - No. 3)

Solve: 2\(^{\sqrt{2x + 1}}\) = 32
13
24
12
11

Тайлбар

2\(^{\sqrt{2x + 1}}\) = 32

2\(^{\sqrt{2x + 1}}\) = 2\(^5\)

\(\sqrt{2x + 1}\) = 5

square both sides

2x + 1 = 5\(^2\)

2x + 1 = 25

2x = 25 - 1

2x = 24

x = \(\frac{24}{2}\)

x = 12

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