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WAEC - Mathematics (2012 - No. 35)

In the diagram, O is a circle centre of the circle PQRS and < PSR = 86o. If < PQR = xo, find x
108o
172o
130o
50o

Тайлбар

xo = 86 x 2(angle at centre = 2 x angle at circumference)

= 172o

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