WAEC - Mathematics (1993 - No. 24)
In the diagram above, QRS is a straight line, QP//RT, PRQ = 56°, ∠QPR =84° and ∠TRS = x°. Find x
28°
40°
44°
84°
124°
Тайлбар
< PQR = 180° - (84° + 56°)
= 40°
\(\therefore\) x = 40° (corresponding angles QP// RT)
In the diagram above, QRS is a straight line, QP//RT, PRQ = 56°, ∠QPR =84° and ∠TRS = x°. Find x
< PQR = 180° - (84° + 56°)
= 40°
\(\therefore\) x = 40° (corresponding angles QP// RT)