WAEC - Further Mathematics (2011 - No. 13)
Find \(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12}\)
-1
\(\frac{-1}{7}\)
\(\frac{1}{7}\)
1
Тайлбар
\(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12} = \frac{3 + 3}{3^{2} - 3 - 12}\)
= \(\frac{6}{-6} = -1\)