WAEC - Further Mathematics (2009 - No. 10)
Given that \(2^{x} = 0.125\), find the value of x.
0
-1
-2
-3
Тайлбар
\(2^{x} = 0.125 = \frac{125}{1000}\)
\(2^{x} = \frac{1}{8} = 8^{-1}\)
\(2^{x} = 2^{-3}\)
\(x = -3\)
\(2^{x} = 0.125 = \frac{125}{1000}\)
\(2^{x} = \frac{1}{8} = 8^{-1}\)
\(2^{x} = 2^{-3}\)
\(x = -3\)