JAMB - Physics (2002 - No. 17)
If tension is maintained on a stretched string of length 0.6m, such that its fundamental frequency of 220Hz is excited, determine the velocity of the transverse wave in the string.
528 ms-1
264 ms-1
132 ms-1
66 ms-1
Тайлбар
in a vibrating string the fundamental frequency is given by fo = v/2L
therefore velocity = 2L x f.
= 2 x 0.6 x 220
= 264 m/s.
therefore velocity = 2L x f.
= 2 x 0.6 x 220
= 264 m/s.