JAMB - Mathematics (1989 - No. 33)
4sin2 x - 3 = 0, find x if 0 \(\geq\) x \(\geq\) 90o
30o
45o
60o
9o
Тайлбар
4 sin2x - 3 = 0
sin2x = \(\frac{3}{4}\)
Sin x = \(\pm\) \(\sqrt{\frac{3}{4}}\)
= \(\pm\) \(\sqrt{\frac{3}{4}}\)
= 60o
sin2x = \(\frac{3}{4}\)
Sin x = \(\pm\) \(\sqrt{\frac{3}{4}}\)
= \(\pm\) \(\sqrt{\frac{3}{4}}\)
= 60o