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JAMB - Mathematics (1986 - No. 42)

In the diagram, PQ and RS are chords of a circle centre O which meet at T outside the circle. If TP = 24cm. TQ = 8cm and TS = 12cm, find TR.
16cm
14cm
12cm
8cm

Тайлбар

PT x QT = TR x TS

24 x 8 = TR x 12

TR = \(\frac{24 \times 8}{12}\)

= = 16cm

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