WAEC - Mathematics (2018 - No. 40)
The solution of x + 2 \(\geq\) 2x + 1 is illustrated
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Paskaidrojums
x + 2 \(\geq\) 2x + 1
x - 2x \(\geq\) 1 - 2
-x \(\geq\) -1
\(\frac{-x}{-1}\) \(\geq\) \(\frac{-1}{-1}\)
x \(\leq\) 1
The solution of x + 2 \(\geq\) 2x + 1 is illustrated
x + 2 \(\geq\) 2x + 1
x - 2x \(\geq\) 1 - 2
-x \(\geq\) -1
\(\frac{-x}{-1}\) \(\geq\) \(\frac{-1}{-1}\)
x \(\leq\) 1