WAEC - Mathematics (1998 - No. 59)
It is observed that \(1 + 3 = 2^2, 1 + 3 + 5 = 3^2, 1 + 3 + 5 + 7 = 4^2. \\If \hspace{1mm}1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 = P^2 find\hspace{1mm}P\)
6
7
8
9
Paskaidrojums
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 = 64
where 64 = 8^2
That is P is 8